What is the osmotic pressure of a 0.065 molar aqueous NaCl at 298 Kelvin?

According to osmotic pressure formula:

π = iCRT

when π is the osmotic pressure

i is van't Hoff factor = 2

R universal gas constant 0.0821

T temperature in Kelvin = 298 K

C is molar concentration of solution = 0.065 M

So by substitution, we will get the osmotic pressure:

∴π = 2 * 0.065 * 0.0821 * 298 = 3.18 atm