23492u undergoes alpha decay. what is the atomic number of the resulting element. express your answer numerically as an integer.

Question

Chemistry

Jackrabbit

24 September, 14:05

23492u undergoes alpha decay. what is the atomic number of the resulting element. express your answer numerically as an integer.

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Answers (1)

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Johnny Andersen · Answer 1

Answer is: mass number of element is 230.

Alpha particle is nucleus of a helium-4 atom, which is made of two protons and two neutrons.

²³ ⁴U → ²³⁰X + α (alpha particle).

Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.