What mass of phosphoric acid (h3po4, 98.0 g/mol) is produced from the reaction of 10.0 g of p4o10 (284 g/mol) with excess water?

When the balanced reaction equation is:

P4O10 + 6H2O→ 4 H3PO4

when we have the mass of P4O10 = 10 g and the molar mass of P4O10=284 g/mol & we have the molar mass of H3PO4 = 98 g/mol so we can get the mass of H3PO4 by substitution by:

mass of H3PO4 = (mass of P4O10) / (molar mass of P4O10) * 4 (mol of H3PO4) * molar mass of H3PO4

∴mass of H3PO4 = (10 / 284) * 4 * 98 = 13.8 g