Calculate the theoretical yield of ammonia produced by the reaction of 100g of H2 gas and 200g of N2 gas

To get the theoretical yield of ammonia NH3:

first, we should have the balanced equation of the reaction:

3H2 (g) + N2 (g) → 2NH3 (g)

Second, we start to convert mass to moles

moles of N2 = N2 mass / N2 molar mass

= 200 / 28 = 7.14 moles

third, we start to compare the molar ratio from the balanced equation between N2 & NH3 we will find that N2: NH3 = 1:2 so when we use every mole of N2 we will get 2 times of that mole of NH3 so,

moles of NH3 = 7.14 * 2 = 14.28 moles

finally, we convert the moles of NH3 to mass again to get the mass of ammonia:

mass of NH3 = no. moles * molar mass of ammonia

= 14.28 * 17 = 242.76 g