62 grams of Zn (C2H3O2) 4 are dissolved to make a 1.5 M solution. How many milliliters of water are needed?

Molarmass of Zn (C2H3O2) 4 is 301.5561 g/mol

moles of

Zn (C2H3O2) 4

= 62 g * 1 mol / (301.5561 g) = 0.2056 mol

concentration = moles / volume

concentration * volume = moles

volume = moles / concentration

volume = 0.2056 mol / 1.5 M

volume = 0.13706 L

volume = 137 mL

volume = 140 mL