How many grams of hcl can be produced if 7.25 g of cl2 is reacted with an unlimited supply of h2?

The equation for the reaction is as follows

H₂ + Cl₂ - - - > 2HCl

the stoichiometry of Cl₂ to HCl is 1:2

this means that for every 1 mol of Cl₂ that reacts, 2 moles of HCl are produced.

Since there's excess of H₂, Cl₂ is the limiting reactant. Number of HCl moles produced are twice the number of Cl₂ moles reacted.

Mass of Cl₂ reacted = 7.25 g

Moles of Cl₂ reacted = 7.25 g / 70.9 g/mol

= 0.10 mol

moles of HCl produced - 0.10 mol x 2

= 0.20 mol

mass of HCl = 0.20 mol x 36.46 g/mol

= 7.29 g