Glucose, C6H12O6, is a good source of food energy. When it reacts with oxygen, carbon dioxide and water are formed. How many liters of CO2 are produced when 126 g of glucose completely react with oxygen? C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (l) + 673 kcal

a. 15.7 L

b. 94.1 L

The number of liters produced when 126g of glucose is completely reacted with O2 is calculated as follows

find the moles of C6H12O6 used that is moles = mass / molar mass

= 126g / 180 g/mol = 0.7 moles

from the equation

C6H12O6 + 6O2 = 6CO2 + 6 H2O

the reacting ratio of C6H12O6 to Co2 is 1:6 therefore the moles of CO2 = 0.7 x6/1 = 4.2 moles

At STP 1 moles of a gas = 22.4 L

what about 4.2 L = how many liters

cross multipication

= (4.2moles x 22.4 L) / 1mole = 94.1 L