Will up-vote

A force of 2,500 pounds drags a truck 30 feet in 1/2 minute.

How much work is accomplished?

How much power was required?

Work = 75,000 ft-lbs, Power = 32, 5000 ft-lbs/sec

Work = 7,500 ft-lbs, Power = 250 ft-lbs/sec

Work = 75,000 ft-lbs, Power = 2,500 ft-lbs/sec

In order to calculate the work done on a body, we find the product of the force applied on the body and the displacement produced in the direction of the force. Mathematically:

Work = Force * displacement

Work = 2,500 * 30

Work = 75,000 ft-lbs

Power is the rate of work done, this is:

Power = Work / time

Power = 75,000 / 30

Power = 2,500 ft-lbs/sec

Work = 75,000 ft-lbs, Power = 2,500 ft-lbs/sec