What mass of lead (density 11.4 g/cm3) would have an identical volume to 20.1 g of mercury (density 13.6 g/cm3) ?

In order to determine the mass of lead, Pb, that would have an identical volume as 20.1 g of mercury, Hg, we first get the equivalent volume of 20.1 g of mercury. This can be done by using the given density of mercury which is equal to 13.6 g/cm^3. This is shown in the following equation:

20.1 g Hg / 13.6g/cm^3 = 1.4779 cm^3 of Hg

Consequently, we use this obtained volume which is the target volume for lead. Again, we make use of the density of the substance, in this case, lead has a density of 11.4 g/cm^3. The resulting equation is then:

11.4 g/cm^3 x 1.4779 cm^3 = 16.8485 g of Pb

Thus, the amount of lead that has an identical volume as 20.1 g of mercury is 16.8485 g Pb.