If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?

The combustion reaction is as expressed,

CxHy + O2 - - > CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,

mass of C in CO2 = (3.14 g) (3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g.

moles of C = 0.86 g C / 12 g = 0.0713

moles of H = 0.14 g H / 1 g = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.