It takes 46 ml of 0.124 m koh to neutralize 28.1 ml of h2so4 solution. what is the concentration of the h2so4 solution? answer in units of moles/liter.

The balanced equation of for the above reaction is as follows;

2KOH + H₂SO₄ - - - > K₂SO₄ + 2H₂O

stoichiometry of KOH to H₂SO₄ is 2:1

the number of KOH moles reacted - 0.124 mol/L x 0.046 L = 0.0057 mol

for complete neutralisation the base should react with acid in 2:1 molar ratio

if 2 mol of KOH reacts with 1 mol of H₂SO₄

then 0.0057 mol of KOH reacts with - 1/2 x 0.0057 mol = 0.0029 mol

the number of H₂SO₄ moles in 28.1 mL - 0.0029 mol

Molarity is number of H₂SO₄ moles in 1 L

therefore number of H₂SO₄ moles in 1 L - 0.0029 mol / 0.0281 L = 0.103 M

molarity of H₂SO₄ is 0.103 mol/L