Ask Question
16 January, 14:36

How many grams of (nh4) 3po4 are needed to make 0.250 l of 0.150 m (nh4) 3po4? hints how many grams of (nh4) 3po4 are needed to make 0.250 l of 0.150 m (nh4) 3po4? 5.47 g 5.59 g 89.5 g 2.52 x 10-4 g?

+5
Answers (1)
  1. 16 January, 17:20
    0
    There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We calculate the mass of the solute by first determining the number of moles needed. And by using the molar mass, we can convert it to units of mass.

    Moles (nh4) 3po4 = 0.250 L (0.150 M) = 0.0375 moles (nh4) 3po4

    Mass = 0.0375 mol (nh4) 3po4 (149.0867 g / mol) = 5.59 g (nh4) 3po4
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many grams of (nh4) 3po4 are needed to make 0.250 l of 0.150 m (nh4) 3po4? hints how many grams of (nh4) 3po4 are needed to make 0.250 ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers