Calculate the ΔHrxn for the following reaction:

CH4 (g) + 2Cl2 (g) - - > CH2Cl2 (g) + 2HCl (g)

Use the following reaction and given ΔH's:

CH4 (g) + Cl2 (g) - - > CH3Cl (g) + HCl (g), ΔH = - 99.60 kJ

CH3Cl (g) + Cl2 (g) - - > CH2Cl2 (g) + HCl (g), ΔH = - 105.8 kJ

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Blaze Cunningham

20 December, 09:37

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Malik Fields · Answer 1

CH4 (g) + 2Cl2 (g) - - > CH2Cl2 (g) + 2HCl (g) ΔH = - 205.4

Calculate the ΔHrxn for the following reaction:CH4 (g) + 2Cl2 (g) - - > CH2Cl2 (g) + 2HCl (g)Use the following reaction and given ΔH's:CH4 (g) + Cl2 (g) - - > CH3Cl (g) + HCl (g), ΔH = - 99.60 kJCH3Cl (g) + Cl2 (g) - - > CH2Cl2 (g) + HCl (g), ΔH = - 105.8 kJ