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15 January, 17:14

If 82.3 l of an ideal gas is cooled from 46 degrees calius to - 166 what will the volume of the gas become

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  1. 15 January, 19:47
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    Temperature is directly related to volume. Note that temperature used is Kelvin, so you need to convert both of them into Kelvin

    With that information, you can derive this equation:

    T1/T2=V1/V2

    V2 = V1*T2 / T1

    V2 = 82.3 * (-166+273.15) / (46+273.15)

    V2 = 82.3 * 107.15 / 319.15

    V2 = 27.63L
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