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3 November, 09:52

If a solution containing 18.0 g of a substance reacts by first-order kinetics, how many grams remain after three half-lives?

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  1. 3 November, 13:48
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    Answer: 2.25 g

    Explanation:

    1) The half-life is the fime for which the initial concentration is decreased by half of the original concentration.

    2) So, after every period of one half-life the concentration of the reactant will decrease by half.

    3) In this case after 3 half-lives, the concentration will decrease by half 3 times which is 2^3 = 8

    So, the amount that will remain will be 18.0 g / 8 = 2.25 g.

    4) You can do it in 3 stages in this way:

    One half-life = > 18.0g / 2 = 9.0 g

    Two half-lives = > 9.0g / 2 = 4.5 g

    Three half-lives = > 4.5 g / 2 = 2.25 g
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