How many grams of water are needed to react with 44.9 grams of li2o?

The grams of water needed to react with 44.9 grams of Li2O is calculated as follows

write the equation for reaction

Li2O + H2O = 2LiOH

find the moles of Li2O = mass/molar mass

= 44.9/29.9 = 1.5 moles

by use of reacting ratio between Li2O to H2O which is 1:1 the moles of H2O is therefore = 1.5 moles

mass is therefore = moles x molar mass

= 1.5 mol x 18 g/mol = 27 grams