Oxygen forms a number of compounds with sulfur, many of which are quite reactive. One such compound is 57.20 % by mass S. Calculate the number of grams of oxygen present in a sample of this compound that contains 50.00 grams of S.

Answer is: number of grams of oxygen present in a sample is 37,41 g.

m (S) = 50 g.

mass percentage (S) = 57,20 % = 0,572.

mass percentage (O) = 100% - 57,20%

mass percentage (O) = 42,8% = 0,428.

m (O) = ?.

make proportion 57,20% : 42,8% = 50 g : m (O)

57,2% · m (O) = 42,8% · 50 g.

m (O) = 42,8% · 50 g : 57,2%.

m (O) = 37,41 g.