Using lewis formulas, assign oxidation states to the atoms in these compounds. assume that sulfur is more electronegative than carbon.

Compound 1: CS₂

Oxidation State of S = - 2

Overall Charge on Molecule = 0

So,

C + (-2) ₂ = 0

C - 4 = 0

C = + 4

Result:

O. S of C = + 4

O. S of S = - 2

Compound 2: CH₃S-S-CH₃ or H₆C₂S₂

Oxidation State of H = + 1

Oxidation State of S = - 2

Overall Charge on Molecule = 0

So,

(H) ₆ + (C) ₂ + (S) ₂ = 0

(+1) ₆ + (C) ₂ + (-2) ₂ = 0

+6 + (C) ₂ - 4 = 0

(C) ₂ = - 6 + 4

(C) ₂ = - 2

C = - 1

Result:

O. S of C = - 1

O. S of S = - 2

O. S of H = + 1