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18 June, 08:30

How much heat in joules is required to heat a 43g sample of aluminum from an initial temperature of 72˚F to a final temperature of 145˚F?

Special heat capacity for aluminum is 0.903 J/g˚C

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  1. 18 June, 09:54
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    The first step to answering this item is to convert the given temperatures in °F to °C through the equation,

    °C = (°F - 32) (5/9)

    initial temperature: 72°F

    °C = (72 - 32) (5/9) = 22.22°C

    final temperature: 145°F

    °C = (145 - 32) (5/9) = 62.78°C

    Substituting to the equation,

    H = mcpdT

    H = (43 g) (0.903 J/g°C) (62.78 - 22.22)

    H = 1574.82 J

    Answer: 1574.82 J
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