How much heat is released when 85.0 grams of liquid water freezes to ice, at 0 degrees celcius

To calculate the amount of heat entering or leaving a system, the equation Q=mcΔT is used.

Explanation:

m = mass (in grams)

c = specific heat capacity (J/g°C)

ΔT = change in temperature (°C)

Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C.

The mass given is 25.0 grams.

As for the change in temperature, I will assume that it start off at room temperature, 25°C.

25°C-0°C=25°C

Q=mcΔT

Q=25grams⋅4.19 J g°C ⋅25°C

Q=2618.75J

Take into account significant figures and the answer should be

2.6⋅ 103 J