What is the empirical formula of a compound composed of 32.9g of potassium and 6.73 g of oxygen

The empirical formula is calculated as follows

step 1; calculate the moles of each element

K = 32.9 g/39 g/mol (molar mass of potassium) = 0.84 moles

O = 6.73 g / 16 g/mol (molar mass of oxygen) = 0.42 moles

step 2; calculate the mole ratio by dividing by smallest number of mole

K = 0.84 / 0.42=2

O = 0.42/0.42 = 1

therefore the empirical formula = K2O