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3 September, 11:14

The molar solubility of calcium fluoride, CaF2, is 2.0 x 10^-4M. What is the concentration of fluoride ion in a saturated solution?

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  1. 3 September, 13:29
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    Answer is: concentration of the fluoride ion is 0.0368 M.

    Chemical reaction: CaF ₂ (s) → Ca²⁺ (aq) + 2F⁻ (aq).

    Ksp = 2.0·10⁻⁴ M.

    Ksp = [Ca² ⁺] · [F⁻ ]².

    [Ca²⁺] = x.

    [F⁻] = 2[Ca²⁺] = 2x.

    Ksp = x · (2x) ².

    2.0·10⁻⁴ = 4x³.

    x = [F⁻] = ∛ (2.0·10⁻⁴ : 4).

    [F⁻] = 0.0368 M.
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