A chemist requires 0.446 mol na2co3 for a reaction. how many grams does this correspond to?

The amount of moles of Na₂CO₃ required = 0.446 moles

to find out the mass of Na₂CO₃ required, we need to find out its molar mass.

Molar mass is the mass of one mole of the element / compound.

molar masses of the elements are as follows;

Na - 23 g/mol

C - 12 g/mol

O - 16 g/mol

Molar mass of Na₂CO₃ can be calculated as follows;

(Na * 2) + C + (O * 3)

(23*2) + 12 + (16*3)

= 46 + 12 + 48

=106 g/mol

1 mol of Na₂CO₃ weighs - 106 g

Therefore 0.446 mol = 106 g/mol * 0.446 mol = 47.27g