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25 November, 21:48

How many grams of acetic anhydride are needed to react with 4.65 g of salicylic acid?

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  1. 25 November, 22:17
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    From the equation, one mole of acetic anhydride is needed to react with one mole of salicylic acid. From the stoichiometry of the equation, we get 4.65 g x 102.10 g acetic anhydride/1 mol divided by 138.13 g salicylic acid per mole. This gives us 3.44 g of salicylic acid.
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