Be sure to answer all parts. how would you prepare benzylamine (c6h5ch2nh2) from c6h5cooh? more than one step is required. qsleft1 edit structure ... qsright1 select the correct reagents for each step. x: nh3, nabh3cn h2, pd-c [1] lialh4, [2] h2o [1] socl2, [2] nh3 y: [1] (ch3) 2culi, [2] h2o [1] lialh4, [2] h2o [1] dibal-h, [2] h2o [1] ch3mgbr, [2] h2o

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Chemistry

Harley Mahoney

8 September, 01:43

Be sure to answer all parts. how would you prepare benzylamine (c6h5ch2nh2) from c6h5cooh? more than one step is required. qsleft1 edit structure ... qsright1 select the correct reagents for each step. x: nh3, nabh3cn h2, pd-c [1] lialh4, [2] h2o [1] socl2, [2] nh3 y: [1] (ch3) 2culi, [2] h2o [1] lialh4, [2] h2o [1] dibal-h, [2] h2o [1] ch3mgbr, [2] h2o

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Doobie · Answer 1

Benzoic Acid is Converted into Benzyl Amine in following steps,

First the - OH group of Benzoic is replaced by - Cl by treating Benzoic acid with Thionyl Chloride.

The Benzoyl Chloride formed is treated with Ammonia, which replaces the - Cl of Benzoyl chloride with - NH₂ forming Benzamide.

Benzamaide on reduction by LiAlH₄ is converted to Benzyl Amine, as the strong reducing agent converts C=O (carbonyl) group into - CH₂ - group.