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6 August, 06:07

A student produces 1.34g of mgnh4po4*6h2o (mm = 245.1 g/mol) from a sample of fertilizer, how grams of phosphorous were in the fertilizer?

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  1. 6 August, 06:29
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    1.34 grams of MgNH4PO4*6H2O

    Molar mass = 245.1 grams per mole

    Moles of MgNH4PO4*6H2O=

    (1.34 grams) (1 mole/245.1 grams fertilizer) = 0.0054671563 moles fertilizer

    MgNH4PO4*6H2O has 1 mole of Phosphorous, so:

    0.0054671563 moles fertilizer (1 mole Phosphorous/1 mole fertilizer)

    0.0054671563 moles Phosphorous (30.97 grams / 1 mole)

    =0.1693178295 grams Phosphorous
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