Determine the Celsius temperature of 2.08 moles of gas contained in a 1.00 L vessel at a pressure of 177 kPa. - 183 Incorrect: Your answer is incorrect. °C

We can use the ideal gas law equation to find the temperature,

PV = nRT

where

P - pressure - 177 kPa

V - volume 1.00 x 10⁻³ m³

n - number of moles - 2.08 mol

R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

T - temperature

substituting these values in the equation

177 x 10³ Pa x 1.00 x 10⁻³ m³ = 2.08 mol x 8.314 Jmol⁻¹K⁻¹ x T

T = 10.2 K

temperature in celsius - 10.2 - 273 = - 262.8 °C