In the redox conversion of Ni2 + to NiO4-, the oxidation number of Ni goes from (-2, 0, + 2) to (-1, + 1, + 7, + 9). Recall that the oxidation number of oxygen is typically - 2.

1. 0; + 9

2. + 2; + 7

3. + 2; - 1

4. - 2; + 9

5. - 2; + 7

6. 0; + 1

7. 0; + 7

8. + 2; + 9

9. - 2; + 1

Oxidation number of an atom is the charge that atom would have if the compound is composed of ions. In neutral substances that contains atoms of one element the oxidation number of an atom is zero. Thus atoms in O2, Ni2, and aluminium all have oxidation number of zero.

In this case, Ni2, the oxidation number of Ni atom is zero,

for NiO4-, assuming oxidation number of Ni is x

(x * 1) + (-2 * 4) = - 1

x = + 7

Therefore, the oxidation number goes from 0 to + 7