What mass will 33.6 l of chlorine gas (cl2) have at stp

The STP stands for standard temperature and pressure which means in a condition where the temperature is 273.15K and the pressure is 0.986atm. In STP, an ideal gas will have a volume 22.4 liters for every mol of gas. Then, the amount of molecule of the 33.6 l of chlorine gas (Cl2) would be:

volume of gas / number of mol = 22.4l/mol

33.6l / number of mol = 22.4l/mol

number of mol = 33.6l / (22.4 liters/mol) = 1.5 moles

The mass of the gas would be: 1.5 moles * 70.906 g/mol = 106.359 grams