What is the mass in grams of 0.433 mol of Ca (NO3) 2

The molar mass of the components making up Ca (NO₃) ₂ are as follows;

Ca - 40 g/mol

N - 14 g/mol

O - 16 g/mol

the molar mass of the compound is calculated as follows;

Ca (NO₃) ₂ - - > 40 + 2 (14 + 16x3)

= 164 g/mol

1 mol of the compound weighs 164 g

Therefore 0.433 mol = 164 g/mol x 0.433 mol

= 71.0g

the mass of 0.433 mol of the compound is 71.0 g