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19 December, 18:45

If δh = - 70.0 kj and δs = - 0.300 kj/k, the reaction is spontaneous below a certain temperature. calculate that temperature.

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  1. 19 December, 20:23
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    The temperature for the reaction is calculated as follows

    delta H / delta S

    delta H=-70 Kj

    delta S = - 0.300 kj/k

    temperature is therefore = - 70kj/-0.300kj/k = 233.33 K
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