A 5.0 gram sample of lead and a 3.2 gram sample of iron are placed into 367 mL of water. What will be the new volume level of water in units of mL?

367.8 mL The density of both lead and iron is greater than the density of water, so they'll both sink. When they sink, the volume of the water plus metals will increase by the volume of the metals. So let's see what those volumes are. Lead has a density of 11.34 g/cm3 Since we have 5.0 grams of lead, the volume will be 5.0 g / 11.34 g/cm3 = 0.440917 cm3 Iron has a density of 7.87 g/cm3 Since we have 3.2 grams of iron, the volume will be 3.2 g / 7.87 g/cm3 = 0.406607 cm3 The total volume will be the sum of the volumes of water, lead, and iron. Giving 367 cm3 + 0.440917 cm3 + 0.406607 cm3 = 367.8475 cm3 Rounding to tenths gives 367.8 cm3 or 367.8 mL