Hi, I can't seem to answer the letter b.--> An empty vial weighs 55.32 g. (a) If the vial weighs 185.56 g when filled with liquid mercury (d 13.53 g/cm3), what is its volume? (b) How much would the vial weigh if it were filled with water (d 0.997 g/cm3 at 25°C) ?,

Question

Chemistry

Branden

29 August, 22:08

Hi, I can't seem to answer the letter b.--> An empty vial weighs 55.32 g. (a) If the vial weighs 185.56 g when filled with liquid mercury (d 13.53 g/cm3), what is its volume? (b) How much would the vial weigh if it were filled with water (d 0.997 g/cm3 at 25°C) ?,

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Answers (1)

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Marin Hart · Answer 1

Subtract the mass when full from the mass when empty.

185.56 - 55.32 = 130.26 g.

Divide by the density of liquid mercury to find the volume.

130.26 g / 13.53g/cm^3 = 9.62601626 cm, the volume of the vial.

If water was used instead of mercury, the fluid mass would be

9.62601626 cm *.997 g/cm^3 = 9.597 g

Adding this to the empty vial mass of 55.32 gives a final mass of 64.916 g.