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4 November, 13:23

What is the volume in l of 3.9 kg of ethylene glycol?

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  1. 4 November, 15:08
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    3.514 l Ethylene glycol has a density of 1.11 g/cmÂł. So divide the given mass by the known density and you'll get the volume. So 3900 g / 1.11 g/cmÂł = 3513.514 cmÂł Since there's 1000 cmÂł per liter, you then need to divide by 1000 to convert from cmÂł to liters. 3513.514 cmÂł / 1000 cmÂł/l = 3.514 l
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