Taking into account the vapor pressure of water, how many moles of hydrogen gas, n, are present in 345 ml at 752 torr and 29 ∘c? the value of the gas constant r is 0.08206 l⋅atm / (mol⋅k). you may also find the conversion

To make things simple, assume ideal gas. Then, we use the ideal gas equation.

PV = nRT

Since we are finding for n, the equation should be rearranged to

n = PV/RT

Make sure you are consistent with your units. If you use R = 0.08206 l⋅atm / (mol⋅k), the pressure should be:

P = 752 torr (1 atm/760 torr) = 0.98947 atm

The volume should be:

V = 345 mL (1 L/1000 mL) = 0.345 L

The temperature should be:

T = 29 + 273 = 302 K

Thus,

n = (0.98947 atm) (0.345 L) / (0.08206 l⋅atm / (mol⋅k)) (302 K)

n = 0.01377 moles of hydrogen gas