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25 June, 00:43

What concentration of the barium ion, ba2+, must be exceeded to precipitate baf2 from a solution that is 1.00*10-2 m in the fluoride ion, f-? ksp for barium fluoride is 2.45*10-5. express your answer with the appropriate units?

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  1. 25 June, 01:56
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    Answer is: concentration of the barium ion is 0,245 M.

    Chemical reaction: BaF₂ → Ba²⁺ + 2F⁻.

    [F⁻] = 1,00·10⁻² M.

    Ksp = 2,45·10⁻⁵.

    Ksp = [Ba²⁺] · [F⁻]².

    [Ba²⁺] = Ksp : [F⁻]².

    [Ba²⁺] = 2,45·10⁻⁵ : (1,00·10⁻² M) ².

    [Ba²⁺] = 0,245 M.
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