A 41.0 ml barium hydroxide solution of molarity 3.41 m is diluted with water to form 279 ml of solution. calculate the molarity of the solution

Using the dilution equation

M1V1=M2V2

M1 is the initial molarity, V1 the initial volume, while V2 is the final volume after dilution, while M2 is the molarity after dilution.

Hence

41 * 3.41 = 279 * M2

M2 = (41 * 3.41) / 279

= 0.5011 M

Therefore; the molarity after dilution is 0.5011 M