If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe (OH) 2 (s) + 2NaCl, how many grams of NaCl would be made?

A. 467.52 g NaCl

B. 1014 g NaCl

C. 233.76 g NaCl

D. 649.05 g NaCl,

Number of moles of FeCl2 used = mass / molar mass

Number of moles = 507/126.751 = 4.

If one mole of Fe reacts with two moles of sodium

Then 4 moles of Fe produces 8 moles of sodium.

Number of moles of sodium = mass/molar mass

Molar mass of sodium chloride = 23 + 35.5 = 58.5 g/mol

Hence mass = 8 * 58.5 = 468 g. Hence Option A.