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24 November, 09:14

The oxidation numbers of nitrogen in NH3, HNO3, and NO2 are, respectively:

A) - 3, - 5, + 4

B) + 3, + 5, + 4

C) - 3, + 5, - 4

D) - 3, + 5, + 4

is it D?

+1
Answers (1)
  1. 24 November, 12:54
    0
    The sum of all the charges of individual atoms sum up to the net charge of the compound / ion.

    In NH₃, overall its a neutral compound, net charge = 0

    oxidation number of N + 3 (oxidation state of H) = 0

    charge of H is - 1

    oxidation number of N + 3 (-1) = 0

    N - 3 = 0

    Oxidation number of N = + 3

    In HNO₃

    oxidation number of O = - 2

    oxidation number of H = + 1

    H + N + 3 (O) = 0

    1 + N + 3 (-2) = 0

    N = + 5

    in NO₂,

    oxidation number of N + 2 (oxidation number of O) = 0

    oxidation number of O = - 2

    N + 2 (-2) = 0

    N = + 4

    oxidation number of N = 4

    answer is

    B) + 3, + 5, + 4
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