What is the final pressure (expressed in atm) of a 3.05 l system initially at 724 mm hg and 298 k, that is compressed to a final volume of 2.60 l at 273 k?

Question

Chemistry

Monteen

16 March, 15:56

What is the final pressure (expressed in atm) of a 3.05 l system initially at 724 mm hg and 298 k, that is compressed to a final volume of 2.60 l at 273 k?

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Answers (1)

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Lorelai Pineda · Answer 1

To answer this question, we will use the following equation:

(P1V1) / T1 = (P2V2) / T2 where:

P1 = 724 mm hg

V1 = 3.05 L

T1 = 298 K

P2 is the unknown we want to find

V2 = 2.6 L

T2 = 173 K

Substitute with the givens to calculate P2 as follows:

(724*3.05) / 298 = (P2*2.6) / 273

P2 = 778.057047 mm Hg = 1.023759 atm