Determine the molar solubility for al (oh) 3 in pure water. ksp for al (oh) 3 = 1.3 x 10-33.

When Al (OH) ₃ dissolves it dissociates as follows;

Al (OH) ₃ - - - > Al³⁺ + 3OH⁻

molar solubility is the number of moles that can be dissolved in 1 L of solution

if the molar solubility of Al (OH) ₃ is x then molar solubility of Al³⁺ is x and OH⁻ is 3x

then solubility product constant - ksp formula is as follows

ksp = [Al³⁺][OH⁻]³

ksp = (x) (3x) ³

ksp = x * 9x³

ksp = 9x⁴

ksp = 1.3 x 10⁻³³

9x⁴ = 1.3 x 10⁻³³

x = 3.4 x 10⁻⁹ M

molar solubility of Al (OH) ₃ is therefore 3.4 x 10⁻⁹ M