The combustion of 987.0 g of methane in the presence of excess oxygen produces 1.543 kg of carbon dioxide. What is the percent yield

Question

Chemistry

Alejandro Levy

5 March, 06:05

The combustion of 987.0 g of methane in the presence of excess oxygen produces 1.543 kg of carbon dioxide. What is the percent yield

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Sonny · Answer 1

Answer is: the percent yield is 56.85%.

Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.

m (CH₄) = 987 g.

n (CH₄) = m (CH₄) : M (CH₄).

n (CH₄) = 987 g : 16 g/mol.

n (CH₄) = 61,68 mol.

From reaction: n (CH₄) : n (CO₂) = 1 : 1.

n (CO₂) = 61,68 mol.

m (CO₂) = 61,68 mol · 44 g/mol.

m (CO₂) = 2714,25 g : 1000 g/kg = 2,714 kg.

yield = 1,543 kg : 2,714 kg · 100 % = 56,85%.