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16 September, 15:32

What is the mass of nickel (ii) nitrate (182.71 g/mol) dissolved in 25.0 ml of 0.100 m ni (no3) 2 solution?

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  1. 16 September, 17:32
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    The mass of ni (NO3) 2 that dissolved in 25.0 ml of 0.100m ni (NO3) 2 solution is calculated as follows

    fin the number of moles = molarity x volume in liters

    =25 x0.100 / 1000 = 2.5 x10^-3 moles

    mass = mass x molar mass

    = 2.5 x10^-3 moles x 182.71 g/mol = 0.457 grams
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