What volume of 0.160 m li2s solution is required to completely react with 130 ml of 0.160 m co no3 2?

The volume of 0.160 m Li2S solution required to completely react with 130 ml of 0.160 CO (NO3) 2 is calculated as below

write the reacting equation

Co (NO3) 2 + Li2S = 2LiNO3 + COS

find the moles of CO (NO3) 2 = molarity x volume

= 130 ml x 0.160=20.8 moles

since the reacting moles between CO (NO3) 2 to LiS is 1:1 the moles of LiS is also 20.8 moles

volume of Lis is therefore = moles of Lis / molarity of LiS

= 20.8/0.160 = 130 Ml