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Today, 06:28

Find the total number of atoms in a sample of cocaine hydrochloride, c17h22clno4, of mass 22.5 mg.

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  1. Today, 06:57
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    Total MW: C: 17 (12.0) = 204.0 H: 22 (1.01) = 22.22 Cl: 1 (35.453) = 35.453 N: 1 (14.0) = 14.0 O: 4 (16.0) = 64.0 Total: 339.7 g/mole Total number of atoms: 17+22+1+1+4 = 45 (22.5 x 10^-3 g) (1 mole/339.7 g) (6.022 x 10^23 molecules/mole) (45 total atoms / molecules) = 1.79 x 10^21 total atoms
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