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8 May, 17:13

What is the final volume of a gas that initially occupies 2.50 l at 298 k and is subsequently heated to 334 k?

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  1. 8 May, 18:11
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    To answer this item, we are to think that the given gas behaves ideally such that the equation,

    PV = nRT

    where P is the pressure, V is volume, n is the number of moles, R is the universal gas constant, and T is the temperature. When all things are equal aside from V and T, the equation becomes,

    V1T2 = V2T1

    Substituting the known values,

    (2.5 L) (334 K) = (V2) (298 K)

    The value of V is equal to 2.8 L.

    Answer: 2.8 L.
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