Ag has an anomalous electron configuration. write the observed electron configuration of ag. express your answer in complete form in order of increasing orbital energy. for example, 1s22s2 should be entered as 1s^22s^2.

In Silver, the 4d orbitals will be completely filled. That implies that it does not have two electrons in the 5s orbital. The electronic configuration of Silver is:

Ag (47) = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^1 4d^10