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7 January, 19:26

A solution is 0.30 m in nh3. what concentration of nh4cl would be required to achieve a buffer solution with a final ph of 9.0? recall the hh equation can be written using ph and pka or poh and pkb. the kb of nh3 is 1.8 x 10-5.

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  1. 7 January, 22:20
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    - first, we have to get POH.

    and when we have PH = 9 so,

    PH+POH = 14

    POH = 14 - 9 = 5

    - then by using this formula of PKa:

    PKa = - ㏒Kb and when we have Kb = 1.8x10^-5 so by substitution:

    PKa = - ㏒ 1.8x10^-5

    ∴PKa = 4.7

    So know we have Pka & POH So by substitution in the following formula w can get the concentration:

    POH = Pka + ㏒[HB]/[B}

    5 = 4.7 + ㏒[HB]/[0.3]

    ∴[HB] (NH4Cl) = 0.599 m
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