Calculate e°cell for a silver-aluminum cell in which the cell reaction is al (s) + 3ag + (aq) → al3 + (aq) + 3ag (s) - 2.46 v 0.86 v - 0.86 v 2.46 v

When E° cell is an electrochemical cell which comprises of two half cells.

So,

when we have the balanced equation of this half cell:

Al3 + (aq) + 3e - → Al (s) and E°1 = - 1.66 V

and we have also this balanced equation of this half cell:

Ag + (aq) + e - → Ag (s) and E°2 = 0.8 V

so, we can get E° in Al (s) + 3Ag (aq) → Al3 + (aq) + 3Ag (s)

when E° = E°2 - E°1

∴E° = 0.8 - (-1.66)

= 2.46 V

∴ the correct answer is 2.46 V