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29 June, 10:15

An ideal gas in a sealed container has an initial volume of 2.55 l. at constant pressure, it is cooled to 18.00 °c where its final volume is 1.75 l. what was the initial temperature?

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  1. 29 June, 12:12
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    Data Given:

    V₁ = 2.55 L

    T₁ = ?

    V₂ = 1.75 L

    T₂ = 18 °C + 273.15 = 291.15 K

    Solution:

    Let suppose the Gas is acting Ideally, Then According to Charle's Law,

    P₁ / T₁ = P₂ / T₂

    Solving for T₁,

    T₁ = V₁ * T₂ / V₂

    Putting Values,

    T₁ = (2.55 L * 291.15 K) : 1.75 L

    T₁ = 424.24 K

    Or,

    T₁ = 151 °C
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